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mrs_skeptik [129]
3 years ago
6

Easy problem lots of points explain how to do it please

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
Kdhdkdbdjdiedbdbjxkxbdjdhx sjsosnddd
wlad13 [49]3 years ago
7 0

Answer:

y= -2+\frac{2}{3}x

Step-by-step explanation:

Multiply both sides by 2

2x=3y+6

Move variable to the left-hand side and change its sing

-3y=6-2x

Divide both sides of the equation by -3

y= -2+\frac{2}{3}x

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5.2x10^8 :)))))))))))))
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3 years ago
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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
Need help with question 1 and 2
olya-2409 [2.1K]
I believe that angle DEF is 29 and angle FEG is 61.
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3 years ago
Please help ASAP I will appreciate it
kolbaska11 [484]

Answer:

2 i think

Step-by-step explanation:

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3 years ago
Which one is the answer?
ziro4ka [17]
Answer: its B because it does not pass the vertical line test
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