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Black_prince [1.1K]
2 years ago
7

Determine the height of a cone that has a diameter of 10 inches and a volume of 225 in^3

Mathematics
1 answer:
zhuklara [117]2 years ago
7 0

Answer:

h= 21.4859173174 in (about)

Step-by-step explanation:

This is a formula to determine the height of a cone: Given radius and volume calculate the height, slant height, lateral surface area and total surface area.

Given r, V find height

h = (3 * v) / (πr2)

h=3x225/π5(10/2=5, to find the radius)x2

h=675/π10

h=675/31.4159265359 (about)

therefore, h= 21.4859173174 in (about)

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Please help :) thank you!
const2013 [10]

Answer:

A

Step-by-step explanation:

just plug in the formula

5 0
3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
2 years ago
A customer buys 40 meters of cable. How many centimeters of cable did the customer buy ? (1 meter = 100 centimeters
storchak [24]

Answer:4000

Step-by-step explanation:40 times 100 is 4000

3 0
2 years ago
Read 2 more answers
Mark and Robyn used base- ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense? Whose model is nonsens
Dima020 [189]

Answer:

Robyn model makes more sense and Marks is nonsense.

Step-by-step explanation:

In this question ,calculations not required .All we have to do is consider each model logically .

Marks

Marks model shows 20 rather than 2 which means 200 is 10 times as much as 20. It does not make any sense.

Robyn

Robyn model shows 2 which means 200 is 100 times as much as 2 and this is not only correct but also makes sense because 100 *2=200

8 0
3 years ago
A data set has a maximum of 84, a minimum of 34, a median of 52.5, an upper quartile of 64, and a lower quartile of 44. Which st
Akimi4 [234]

Answer:

A box and whiskers plot has a box whose endpoints are the interquartile range (25th percentile and 75th percentile), has a dividing line at the median, aka the 50th percentile, and whiskers that extend out to the minimum and the maximum of the data.

Let's sort the info for ease of reference:

min 34, lower quartile 44, median 52.5, upper quartile 64, max 84.

OK, let's go through the statements.

A. The box will go from 44 to 64.

The box goes from the lower quartile to the upper quartile, TRUE

B. A line dividing the box will be at 54.

There's no 54 mentioned at all, FALSE

C. The left whisker will go from 34 to 52.5.

The left whisker goes from the minimum to the lower quartile, 34 to 44 here, FALSE.

D. The right whisker will go from 44 to 84.

The right whisker goes from the upper quartile to the max, 64 to 84 here.  FALSE

If this could help, please mark me brainliest! Have an awesome day too!

4 0
2 years ago
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