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3 years ago

12

initially, there were the same number of blue marbles and red marbles in a bag. John took out 5 blue marbles and then there were

twice as many red marbles as blue marbles in the bag. how many red marbles are there in the bag

1 answer:

tester [92]3 years ago

6 0

10 red marbles

Multiply the # of blue marbles by 2 (since there was TWICE as many red marbles), and you have your answer (above)

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What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?

Oxana [17]

Answer:

$\displaystyle d = 18$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (21, 13)

Point (3, 13)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(3-21)^2+(13-13)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-18)^2+(0)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{324+0}$
[√Radical] Add: $\displaystyle d = \sqrt{324}$
[√Radical] Evaluate: $\displaystyle d = 18$

5 0

3 years ago

Model how to factor the polynomial 2x^3-8x^2+3x-12

san4es73 [151]

$2x^3-8x^2+3x-12=2x^2(x -4)+3(x -4)=(x -4)(2x^2+3)$

6 0

3 years ago

Since an instant replay system for tennis was introduced at a major tournament, men challenged 1406 referee calls, with the re

erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

P1 - P2 = difference in the proportion of men and women challenges for calls.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (416 + 217)/(1406 + 778) = 0.29

1 - pc = 1 - 0.29 = 0.71

z = (P1 - P2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.3 - 0.28)/√(0.29)(0.71)(1/1406 + 1/778) = 0.02/√0.00553857907

z = 0.99

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

7 0

3 years ago

Each pack of batteries cost $21. How many i can buy if i have $63?

Rashid [163]

Each pack of batteries cost $21 each.
And then you have $63.

The operation to be used: Division.

63 ÷ 21 ==

Answer: 3

= You can buy 3 packs of batteries with your $63.

6 0

3 years ago

Read 2 more answers

What is the Greatest Common Factor of x^4 and x^3?

hammer [34]

Judging by the question I noticed that the two both share x^3 in common. You can divide x^4 by x^3 and get x as a result, and x^3 can still divide into itself.

Thus your answer should be C, x^3

5 0

3 years ago