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3 years ago

How to find a mean absolute deviation

1 answer:

3 0

1. To find the mean absolute deviation of the data, start by finding the mean of the data set.

2. Find the sum of the data values, and divide the sum by the number of data values.

3. Find the absolute value of the difference between each data value and the mean: [data value – mean].

4. Find the sum of the absolute values of the differences.

5. Divide the sum of the absolute values of the differences by the number of data values.

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3 years ago

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mixas84 [53]

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3 years ago

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Please help thank you

aivan3 [116]

Answer:

a = 4

b = 11

Step-by-step explanation:

To convert the recurring decimals into fraction we will follow the following process.

Given recurring decimal is 0.36363636....

Let x = 0.363636......... (1)

Multiply this decimal with 100.

100x = 36.36363636...........(2)

Now subtract expression (1) from expression (2)

100x = 36.363636.......

x = 0.363636.......

99x = 36

x = $\frac{36}{99}$

x = $\frac{4}{11}$

Since, $x=\frac{a}{b}=\frac{4}{11}$

a = 4 and b = 11 will be the answer.

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3 years ago

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kati45 [8]

67Answer:67

Step-by-step explanation:

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3 years ago

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How do i solve this?

Law Incorporation [45]

Answer:

$\large\boxed{x$

Step-by-step explanation:

$-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\\\\\text{Find common denominator of the fractions}\\\\2,\ 3,\ 5\to2\cdot3\cdot5=30\\\\-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\qquad\text{multiply both sides by 30}\\\\30\!\!\!\!\!\diagup^{15}\left(-\dfrac{1}{2\!\!\!\!\diagup_1}x\right)+30\!\!\!\!\!\diagup^{10}\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)>30\!\!\!\!\!\diagup^{6}\left(\dfrac{3}{5\!\!\!\!\diagup_1}\right)\\\\-15x+10>(6)(3)\\\\-15x+10>18\qquad\text{subtract 10 from both sides}$

$-15x>8\qquad\text{change the signs}\\\\15x$

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4 years ago