Question

A person is standing exactly 36 ft from a telephone pole. There is a 30 degree angle of elevation from the ground to the top of the pole. What is the height of the pole?

Answer 1

A person stands at point A. BC is a telephone pole.

$tanA = \frac{BC}{AB} \ \ \to \ \\BC = AB * tanA = 36 * \frac{ \sqrt{3} }{3} =12 \sqrt{3} \approx 20.78 \ ft.$

Answer 2

Answer:

PQ = 20.78 feet

Step-by-step explanation:

From the attached figure, QR = 36 ft

The angle of elevation from the ground to the top of the pole, $\theta=30^{\circ}$

Let the height of the pole is PQ. We can calculate the height of the pole using trigonometry as :

$tan\theta=\dfrac{PQ}{QR}$

$PQ=QR\times tan\theta$

$PQ=36\times tan(30)$

PQ = 20.78 feet

So, the height of the pole is 20.78 feets. Hence, this is the required solution.