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LenaWriter [7]
3 years ago
8

An object has an initial velocity of 15 m/s. How long must it accelerate at a constant rate of 3 m/s before its final velocity i

s
equal to twice its initial velocity?
Physics
1 answer:
melomori [17]3 years ago
3 0

Answer: 15 m/s

Explanation:

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An old iron beam was coated with an unknown metal. there is a crack on the coating and it is observed that the iron is rusting a
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4 years ago
The radius RH of a black hole, also known as the event horizon, marks the location where not even light itself can escape from t
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Solution:

a) We know acceleration due to gravity, g = GM/r²

Differential change, dg/dr = -2GM/r³

Here, r = 50*Rh = 50*2GM/c² = 100GM/c ²

My height, h=dr = 1.7 m

Difference in gravitational acceleration between my head and my feet, dg = -10 m/s²

or,   dg/dr = -10/1.7 = -2GM/(100GM/c²)³

or,     5.9*100³*G²*M² = 2c⁶

or,   M = 0.59*c³/(1000G) = 2.39*1032 kg = [(2.39*1032)/(1.99*1030 )]Ms = 120*Ms

Mass of black hole which we can tolerate at the given distance is 120 time the mass of Sun.

b) This limit an upper limit ,we can tolerate smaller masses only.

4 0
3 years ago
What happens when all the external forces on a system are balanced ?
Akimi4 [234]

Equilibrium refers to a state in which all of the external forces on an object all balance each other such that there is no net effect (net force equals 0). An object in equilibrium will not experience acceleration, and will either remain at rest, or continue moving at a constant velocity. Here's a simple example, pick up a book (or any random object) and hold it up in the air. The book is now in equilibrium, the downwards force of gravity is perfectly countered by the upwards force that you are applying to it. Notice that the object neither falls nor goes upwards (i.e. no acceleration). Now let go of the book, notice how it falls downwards till it hits the ground (or whatever was beneath it). That is because without the upwards force applied by your hand, the object is no longer in equilibrium, and the force of gravity takes over until it is in equilibrium again.

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3 years ago
A car initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at a c
Kitty [74]
We calculate the difference between the two velocities,
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Then, convert the difference into units of m/s
                         100 km/h x (1000 m/ 1 km) x (1 hour / 3600 s)  = 27.78 m/s
Then divide the difference by time.
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(2) In terms of g,
                               x = 2.65 / 9.80 = 0.27
  Therefore, the answer would be,
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C that’s the answer
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