Answer:
3.6 x 10⁻⁷ H
Explanation:
C = capacitance of the capacitor = 6.57 x 10⁻¹² F
L = inductance of the inductor = ?
f = frequency of broadcasting system = 103.9 MHz = 103.9 x 10⁶ Hz
frequency is given as


Inserting the values
L = 3.6 x 10⁻⁷ H
Answer:
1.23 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 11.1 m/s
t = 9 s
Find: a
Equation:
v = at + v₀
Plug in:
11.1 m/s = a (9 s) + 0 m/s
a = 1.23 m/s²
The runner's acceleration is 1.23 m/s².
The dots in the Lewis dot structure symbolize an atom's elements.
<span>Since Na^+ is a positive ion (cation) with a charge of +1, it indicates that it has lost an electron. </span>
<span>Since Na had one electron, to begin with, and it is now lost, Na^+ will have no dots. However, the charge must still be written as a superscript. </span>
<span>Therefore, the Lewis dot structure for Na^+ is just Na^[+] </span>
The wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons is <u>62. 8 nm.</u>
Wavelength is the distance among the same points (adjacent crests) within the adjoining cycles of a waveform signal propagated in space or along a cord. In wi-fi structures, this period is typically specified in meters (m), centimeters (cm), or millimeters (mm).
The wavelength is the distance between wave crests, and it is going to be the same for troughs. The frequency is the variety of vibrations that skip over a given spot in one 2nd, and it's far measured in cycles consistent with the second (Hz) (Hertz).
Frequency is the ratio of pace and wavelength in relation to speed. In comparison, wavelength refers to the ratio of pace and frequency. Audible sound waves are characterized by way of a frequency range of 20 to 20 kHz. In contrast, the variety of wavelengths of visible light is from four hundred to seven hundred nm.
<u>calculation:-</u>
*E=hc/λ
1.91 × 10^6 J = (6.62610⁻³⁴) (3.00*10⁸) / λ
λ= (6.62610⁻³⁴) (3.00*10⁸) / 1.91 × 10⁶ J
λ= 1.0410⁻³¹× 10⁻⁹ × 6.022*10²³
=<u> 62. 8 nm </u>
Learn more about wavelength here:-brainly.com/question/10728818
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Answer:
Information Security.
Is the most correct answer for this question.