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gogolik [260]
3 years ago
10

How many tiles would I need to by if each tile was 2ft by 2Ft and the square footage was 69X69

Mathematics
1 answer:
valina [46]3 years ago
3 0
This is the formula you would use to calculate how many tiles you would need.

# of tiles you need = Total square footage ÷ square footage of each tile 


Total square footage: 69x69 = 4761 square feet
Square footage of each tile = 2x2 = 4 square feet

# of tiles you need =
4761 ÷ 4 = 1190.25 

You will need 1190.25 tiles.
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Which expression can be used to find the surface area of the following triangular prism? *picture of a triangular prism* Choose
KIM [24]

Answer:

A. 24+24+120+160+200

Step-by-step explanation:

Surface area of the triangular prism= addition of the area of each shape that forms the prism

There are two triangles

Area of a triangle=1/2*base*height

=1/2*8*6

=1/2*48

=24

Area of two triangles=24+24

There are 3 rectangles with different dimensions

Back rectangle=length×width

=20×6

=120

Bottom rectangle=length ×width

=20x8

=160

Top rectangle=length × width

=20×10

=200

Surface area =Area of two triangles + Back rectangle + Bottom rectangle + Top rectangle

=24+24+120+160+200

5 0
2 years ago
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7b + 15 +4 it says write two equivalent expressions.Help
VARVARA [1.3K]

Answer:

1. 4b+3b+15+4

2. 7b+19

Step-by-step explanation:

Both are equivalent expressions :))

7 0
2 years ago
Simplificar: 8 – 14 + 7 +9 <br>​
jeka57 [31]

Step-by-step explanation:

this is your answer.............

6 0
2 years ago
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Can anyone help me with this Midterm Advanced Algebra problem. (DONT ANSWER IF YOUR NOT SURE)
tigry1 [53]

Answer:

y = -1/2x + 13/2

Step-by-step explanation:

The slope of a line that is perpendicular to a line will be a negative reciprocal. When you rewrite 2x-7=8 into slope-intercept form, you get y=2x-8. The negative reciprocal of the slope 2x is -1/2x. There is only one option with this slope. If you're still not sure then you can use a graphing calculator to check this. An online one would be desmos

3 0
2 years ago
I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
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