Answer:
9
Step-by-step explanation:
Let the two perfect cubes be x and y where x > y.
According to the given conditions:
![{x}^{3} - {y}^{3} = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\ {x}^{3} - {7}^{3} = 386 \\ {x}^{3} - 343 = 386 \\ {x}^{3} = 343 + 386 \\ {x}^{3} = 343 + 386 \\ {x}^{3} = 729 \\ x = \sqrt[3]{729} \\ x = 9](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20-%20%20%7By%7D%5E%7B3%7D%20%20%3D%20386...%281%29%20%5C%5C%20y%20%3D%207...%282%29%20%5C%5C%20plug%20%5C%3A%20y%20%3D%207%20%5C%3A%20in%20%5C%3A%20equation%20%5C%3A%20%281%29%20%5C%5C%20%20%7Bx%7D%5E%7B3%7D%20%20-%20%20%7B7%7D%5E%7B3%7D%20%20%3D%20386%20%5C%5C%20%7Bx%7D%5E%7B3%7D%20%20-%20%20343%20%3D%20386%20%5C%5C%20%7Bx%7D%5E%7B3%7D%20%20%20%20%20%3D%20343%20%20%2B%20%20386%20%5C%5C%20%7Bx%7D%5E%7B3%7D%20%20%20%20%20%3D%20343%20%20%2B%20%20386%20%5C%5C%20%7Bx%7D%5E%7B3%7D%20%20%20%3D%20729%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B729%7D%20%20%5C%5C%20x%20%3D%209)
Thus the cube root of the larger number is 9.
We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
(70x10)+(6x1)+(4x1/10)+(2x1/100)+(9x1/1000)
Answer:
1521.16402
Step-by-step explanation:
use fraction- division format

Multiply the numerator and denominator by 100

Reduce by 2

Now do long division
1521. 164022
189|287500
- 189
985
- 945
400
- 378
220
- 189
310
- 189
1210
- 1134
760
- 756
40
- 0
400
- 378
22
Answer:
7 buses
Step-by-step explanation:
51 divided by 8 = 6 and you still have 3 students letf so you have to use one more bus