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2 years ago

PLS HELP ME ASAP FOR ALL 6!! (SHOW WORK!!) + LOTS AND LOTS OF POINTS!!! GIVING THANKS!!

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

4 0

This is the answer for #1

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Elan Coil [88]

Answer:

see explanation

Step-by-step explanation:

The diagrams show triangular figures

The first figure has 1 dot

The second has 1 + 2 = 3 dots

The third has 3 + 3 = 6 dots

The fourth has 6 + 4 = 10 dots

Note the pattern is + 2 , + 3, + 4

Thus the fifth pattern is 10 + 5 = 15 dots

5 0

2 years ago

Consider the table of values below.

Setler [38]

Answer:

f(x)=12x-5

Step-by-step explanation:

-5 is the y-intercept since f(1)=0

the difference from -5 and 7 (7-(-5) or 7+5) is 12 and 12/1 equals 12

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2 years ago

3.25 + 3 tenths A.6.25 B.3.55

strojnjashka [21]

Answer:

Step-by-step explanation:

3.25+.3=3.55

4 0

3 years ago

Read 2 more answers

How many ways can a president, vice president, and secretary be selected from a class of 30 students? a. 90 b. 2,068 c. 4,060 d.

Ad libitum [116K]

Answer:

the answer to your question should be 2,068

Step-by-step explanation:

i hope i am right but i think so

7 0

2 years ago

Consider this right triangle. 21 29 20 Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

The complete question is

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

4 0

2 years ago

PLS HELP ME ASAP FOR ALL 6!! (SHOW WORK!!) + LOTS AND LOTS OF POINTS!!! *GIVING THANKS!!*

PLS HELP ME ASAP FOR ALL 6!! (SHOW WORK!!) + LOTS AND LOTS OF POINTS!!! GIVING THANKS!!