Help plsss it’s urgent!!!!!

Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = $\frac{p x_{2}+q x_{1}}{p+q}$

y = $\frac{p y_{2}+q y_{1}}{p+q}$

From the question

$x_{1}$ = 2

$x_{2}$ = ?

x = 4

$y_{1}$ = -1

$y_{2}$ = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = $\frac{p x_{2}+q x_{1}}{p+q}$

4 = $\frac{1(x_{2})+4(2) }{1+4}$

4 = $\frac{x_{2}+8}{5}$

$x_{2}$ + 8 = 20

$x_{2}$ = 12

Also

y = $\frac{p y_{2}+q y_{1}}{p+q}$

1 = $\frac{y_{2}+4(-1)}{5}$

$y_{2}$ - 4 = 5

$y_{2}$ = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

5 0

3 years ago

The graph shows a probability distribution. What is P(X<5)

Thepotemich [5.8K]

Answer:

P(x < 5) = 0.70

Step-by-step explanation:

Note: The area under a probability "curve" must be = to 1.

Finding the sub-area representing x < 5 immediately yields the desired probability.

Draw a dashed, vertical line through x = 5. The resulting area, on the left, is a trapezoid. The area of a trapezoid is equal to:

(average length)·(width, which here is:

2 + 5

----------- · 0.02 = (7/2)(0.2) = 0.70

2

Thus, P(x < 5) = 0.70

7 0

3 years ago

The graph below represents the solution set of which inequality?

natulia [17]

Answer:

option: B ( $x^2+2x-8$ ) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

$x^2-2x-8$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8$

⇒ $x(x-4)+2(x-4)=0$

⇒ $(x+2)(x-4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x+2>0$ and $x-4$

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

$x+2$ and $x-4>0$

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

$x^2+2x-8$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8$

⇒ $x(x+4)-2(x+4)$

⇒ $(x-2)(x+4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x-2>0$ and $x+4$

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

$x-2$ and $x+4>0$

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

$x^2-2x-8>0$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8>0$

⇒ $x(x-4)+2(x-4)>0$

⇒ $(x-4)(x+2)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x+2>0$ and $x-4>0$

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

$x+2$ and $x-4$

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

$x^2+2x-8>0$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8>0$

⇒ $x(x+4)-2(x+4)>0$

⇒ $(x-2)(X+4)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x-2$ and $x+4$

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

$x-2>0$ and $x+4>0$

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.

5 0

3 years ago

Can anyone one help me with this question

n200080 [17]

<h2>Answer:</h2><h2>Option A is the answer </h2><h2>let a be no of adult and b be the no of children</h2><h2>total money made by park =$55157</h2><h2 /><h2>Given equation </h2><h2>$19 per adult =19a</h2><h2>$9.5 per children=9.5c</h2><h2>total people =3806</h2><h2>19a+9.5c=3806</h2><h2>a+c=55157</h2><h2 /><h2 /><h2>FOLLOW MEH✌✌✌✌✌✌</h2>

5 0

3 years ago

How do you solve the photo below

VikaD [51]

Answer:

6

Step-by-step explanation:

6 0

3 years ago

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