The output would depend on the input so relating this to the question, the input is the time (in minute) and the output is the amount of water left in the tank
We can give a letter 't' for the time, the input, and f(t) for the output
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The original amount of water in the tank is 10450, so this will be the fixed constant.
The amount of water lost per minute is 270 so this will be the term that varies depends on the variable of time, we write this as 270t
The function is given f(t) = 10450 - 270t
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Given, t = 10
f(10) = 10450 - 270(10)
f(10) = 7750 ml
2a/5b = 6
(2a-5b)/5b could be written as: (2a/5b) -(5b/5b)
Repace by its equivalent value (6) -(1) = 5
Answer:
Step-by-step explanation:
Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE
Triangle AED ||| BDE Angle angle congruent
... By compendo and dividendo
Thus proved
Since two lines are parallel we have corresponding angles equal and also
sides will be proportional in similar triangles
Using that and adjusting compendo and dividendo we get the desired result
I think the answer might be B
<h3>
Answers:</h3>
Variation Constant: k = 7/6
y = 245/6 when x = 7 and z = 5
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Explanation:
"y varies jointly as x and z" means that y = kxz
We have (x,y,z) = (4,14,3) as one triple, so,
y = kxz
14 = k*4*3
14 = 12k
12k = 14
k = 14/12
k = 7/6 is the variation constant
The equation goes from y = kxz to y = (7/6)xz
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Plug in x = 7 and z = 5 to find y
y = (7/6)xz
y = (7/6)*7*5
y = (7/6)*(7/1)*(5/1)
y = (7*7*5)/(6*1*1)
y = 245/6
