Equation 1) x + 6y = 2
Equation 2) 5x + 4y = 36

Multiply all of equation 1 by 5.

1) 5(x + 6y = 2)

Simplify.

1) 5x + 30y = 10
2) 5x + 4y = 36

Subtract equations from one another.

26y = -26

Divide both sides by 26.

y = -1

Plug in -1 for y in the first equation.

x + 6y = 2

x + 6(-1) = 2

Simplify.

x - 6 = 2

Add 6 to both sides.

x = 8

D : (8, -1)

~Hope I helped!~

8 0

2 years ago

Find the equation of the circle whose center and radius are given.

trapecia [35]

(x – h)² + (y – k)² = r²

Fill in the numbers

(x – 7)² + (y +3)² = 49

6 0

3 years ago

Read 2 more answers

....sigh.... Shout out to Taater for being helpful in times of need :3

Ne4ueva [31]

Answer:

Taater is a good friend of mine.

Step-by-step explanation:

The answer would be the third option, hope I'm just as helpful in times of need if its possible to subtract those then it's 100% the first option. Sorry don't exactly know this, so I'm at least trying to help.

3 0

3 years ago

The equation x2 - 12x - 60 = -y2 - 4y describes a circle in the coordinate plane. find the radius of the circle and the coordina

34kurt

Answer:

r = 10 , centre = (6, - 2 )

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² - 12x - 60 = - y² - 4y ( add y² + 4y to both sides )

x² - 12x + y² + 4y - 60 = 0 ( add 60 to both sides )

x² - 12x + y² + 4y = 60

using the method of completing the square

add ( half the coefficient of the x and y terms )² to both sides

x² + 2(- 6)x + 36 + y² + 2(2)y + 4 = 60 + 36 + 4

(x - 6)² + (y + 2)² = 100 ← in standard form

with centre = (6, - 2 ) and r = $\sqrt{100}$ = 10

8 0

1 year ago