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Nadya [2.5K]
3 years ago
12

A. x=51, y=63b. x=77, y=63c x=63, y=77d x=77, y=65

Mathematics
2 answers:
vekshin13 years ago
5 0
The answer is b. x=77, y=63
Triss [41]3 years ago
4 0
The answer is B. x=77 and y=63
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Can someone help ?
andreev551 [17]

Answer:

A 234.11

Step-by-step explanation:

= 234.11148454551 feet^{3}  is what you get lol

8 0
2 years ago
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The sum of two numbers is 65. The larger number is 5 more than the smaller number. What are the numbers?
ipn [44]

Answer:

30 and 35

Step-by-step explanation:

Put this question into equation form:

Let x be the smaller number, if the larger number is 5 more and the total is 65:

x + 5 + x = 65

2x + 5 = 65

Subtract 5 from both sides

2x + 5 - 5 = 65 - 5

2x = 60

Divide both sides by 2:

2x ÷ 2 = 60 ÷ 2

x = 30

As the larger number is 5 bigger:

30 + 5 = 35

So the two numbers are 30 and 35.

Hope this helps!

8 0
2 years ago
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You invest $1300 in account that has an annual interest rate of 5% compounded annually. How much money will be in the account af
deff fn [24]
If you think about it and you use a calculator and do 1300×5% it will give you a number and divide it by 10 and there you should get you answer like that.
4 0
3 years ago
How long will it take $5500 to grow to $7400 at an interest rate of 5% it the interest is compounded continuouslyRound the numbe
Thepotemich [5.8K]

Answer:

 5.93 years

Step-by-step explanation:

The continuous compounding formula tells you the amount after t years will be ...

  A = Pe^(rt) . . . . principal P compounded continuously at annual rate r for t years

  7400 = 5500e^(0.05t)

  ln(7400/5500) = 0.05t . . . . divide by 5500, take natural logs

  t = 20×ln(74/55) ≈ 5.93

It will take about 5.93 years for $5500 to grow to $7400.

8 0
2 years ago
*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts
Nataly [62]

Answer: Assuming the function is g(x)=\frac{2x+1}{x-3}:

The x-intercept is (\frac{-1}{2},0).

The y-intercept is (0,\frac{-1}{3}).

The horizontal asymptote is y=2.

The vertical asymptote is x=3.

Step-by-step explanation:

I'm going to assume the function is: g(x)=\frac{2x+1}{x-3} and not g(x)=2x+\frac{1}{x}-3.

So we are looking at g(x)=\frac{2x+1}{x-3}.

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

0=\frac{2x+1}{x-3}

A fraction is only 0 when it's numerator is 0.  You are really just solving:

0=2x+1

Subtract 1 on both sides:

-1=2x

Divide both sides by 2:

\frac{-1}{2}=x

The x-intercept is (\frac{-1}{2},0).

The y-intercept is when x is 0.

Replace x with 0.

g(0)=\frac{2(0)+1}{0-3}

y=\frac{2(0)+1}{0-3}  

y=\frac{0+1}{-3}

y=\frac{1}{-3}

y=-\frac{1}{3}.

The y-intercept is (0,\frac{-1}{3}).

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is y=\frac{2}{1}.  After simplifying you could just say the horizontal asymptote is y=2.

Or!

I could do some division to make it more clear.  The way I'm going to do this certain division is rewriting the top in terms of (x-3).

y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}

y=2+\frac{7}{x-3}

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0
3 years ago
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