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3 years ago

What is the equation of the line that passes through the points (-7,-7) and (-7,4)

Mathematics

1 answer:

musickatia [10]3 years ago

4 0

Answer:

Step-by-step explanation:

The equation of a line

y = mx + c

y - intercept point y

m - slope of the line

x - intercept point x.

c - intercept of the line

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given two points

( -7 , -7) ( -7 , 4)

x1 = -7

y1 = -7

x2 = -7

y2 = 4

Insert the values into the equation

m = 4 - (-7) / -7 -(-7)

m = 4 + 7 / -7 + 7

m = 11/ 0

Step 2: sub any of the two points given into the equation

y= mx + c

y = 11/0x + c

(-7 ,4 )

x = -7

y = 4

4 = 11/0(-7) + c

4 = -77/0 +c

-77/0 is math error which means that the points are not correct

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Calculate the slope of each segment (just need a couple example problems and step by step, no need to answer all. Will mark brai

Tpy6a [65]

Answer:

12) Line segment AB

$m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}$

13) Line segment CD

$m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}$

14) Line segment EF

$m_{EF} = \frac{7-11}{4-3}= -4$

15) Line segment GH

$m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}$

16) Line segment IJ

$m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}$

17) Line segment KL

$m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}$

18) Line segment MN

$m_{MN} = \frac{5-5}{3-(-4)} = 0$

19) Line segment OP

$m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}$

20) Line segment QR

$m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}$

21) Line segment ST

$m_{ST} = \frac{-2-(-3)}{10-9} = 1$

Step-by-step explanation:

Coordinates are now described: $A(x,y) = (4,4)$ , $B(x,y) = (10, 7)$ , $I(x,y) = (-6, 4)$ , $J(x,y) = (0,0)$ , $Q(x,y) = (-7,11)$ , $R(x,y) = (-2,7)$ , $C(x,y) = (13,11)$ , $D(x,y) = (15, 6)$ , $K(x,y) = (-2, -3)$ , $L(x,y) = (5,-2)$ , $S(x,y) = (9,-3)$ , $T(x,y) = (10, -2)$ , $E(x,y) = (3, 11)$ , $F(x,y) = (4,7)$ , $M(x,y) = (-4,5)$ , $N(x,y) = (3, 5)$ , $G(x,y) = (6,2)$ , $H(x,y) = (8,5)$ , $O(x,y) = (13,-2)$ , $P(x,y) = (13,4)$

The slope of each line segment is calculated by applying definition of secant line:

12) Line segment AB

$m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}$

13) Line segment CD

$m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}$

14) Line segment EF

$m_{EF} = \frac{7-11}{4-3}= -4$

15) Line segment GH

$m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}$

16) Line segment IJ

$m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}$

17) Line segment KL

$m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}$

18) Line segment MN

$m_{MN} = \frac{5-5}{3-(-4)} = 0$

19) Line segment OP

$m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}$

20) Line segment QR

$m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}$

21) Line segment ST

$m_{ST} = \frac{-2-(-3)}{10-9} = 1$

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When solving a literal equation, what is the trick for isolating a variable that appears more than once?

Paha777 [63]

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Answer:

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