Question

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25.

Answer 1

Answer:

Step-by-step explanation:

As per the question statement, a₁ is -6.25 and common ratio (r) is 1.25.

Therefore, the six terms of finite sequence would be as per the following equation $f(n) = a1(r)^{n-1}$. Thus, the series would be

1. a1 = -6.25
2. a2 = -6.25*r = -6.25*(1.25) = -7.8125
3. a3 = -6.25*r^2 = -6.25*(1.25)^2 = -9.765625
4. a4 = -6.25*r^3 = -6.25*(1.25)^3 = -12.20703125
5. a5 = -6.25*r^4 = -6.25*(1.25)^4 = -15.2587890625
6. a6 = -6.25*r^5 = -6.25*(1.25)^5 = -19.073486328125

So the points on the graph will be on following points,

(1, -6.25), (2, -7.8125), (3, -9.765625), (4, -12.20703125), (5, -15.2587890625), (6, -19.073486328125).

The graph would look like as attached.