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3 years ago

I have attached the question :)

Mathematics

2 answers:

Yakvenalex [24]3 years ago

6 0

The first one

Explanation:

larisa86 [58]3 years ago

4 0

Answer:

The first one

Step-by-step explanation:

the X values are all diffrent

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A cocktail nut mix should have the following minimum requirements in a can of 1 pound being sold at $3.99 a can at retail stores

Misha Larkins [42]

Answer:

Nut

Step-by-step explanation:

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3 years ago

Please help I will reward Brainly

grigory [225]

V=(4/3)(pi)(r^3)
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3 years ago

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

Lunna [17]

Answer:

x = 2010

Step-by-step explanation:

It is difficult separating and organizing the data. The best I can see is that the question is asking what is the value of x to make f(x) = t(x) true. x = 2010 is a year in which enrollment was the same, 740, in both f and t.

3 0

2 years ago

I need help finding this answer to this inequality -10[9-2x]-x≤2x-5

Ad libitum [116K]

Answer:

x≤5

Step-by-step explanation:

-10(9-2x)-x≤2x-5

-90+20x-x≤2x-5

19x-2x≤90-5

17x≤85

x≤85/17

x≤5

8 0

3 years ago

Luisa is planning a bridal shower for her best friend. At the party, she wants to serve 3 beverages, 3 appetizers, and 3 dessert

Vladimir79 [104]

Answer:

Luisa can pick the food and drinks to serve at the bridal shower in 15,615,600 different ways.

Step-by-step explanation:

Fundamental counting principle:

States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.

Also

The order in which the food and drinks are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Beverages:

3 from a set of 15. So

$B = C_{15,3} = \frac{15!}{3!12!} = 455$

Appetizers:

3 from a set of 10. So

$A = C_{10,3} = \frac{10!}{3!7!} = 120$

Desserts:

3 from a set of 13. So

$D = C_{13,3} = \frac{13!}{3!10!} = 286$

How many different ways can Luisa pick the food and drinks to serve at the bridal shower?

By the fundamental counting principle, as beverages, appetizers and desserts are independent:

$T = B*A*D = 455*120*286 = 15,615,600$

Luisa can pick the food and drinks to serve at the bridal shower in 15,615,600 different ways.

4 0

4 years ago