Which microscope did Anton van Leeuwenhoek use to observe single-celled organisms?

Biology

2 answers:

likoan [24]3 years ago

8 0

Anton van Leeuwenhoek learned to grind lenses ( 1668) and develop simple microscopes.

Leeuwenhoek heated the middle of a small soda glass rod , over a flame. On pulling apart the two ends, the glass rod elongated into thin whiskers .
Heating the end of this whisker resulted in a tiny high quality glass sphere. These glass spheres then became the lens of his microscope, with the smallest sphere providing the greatest magnification.

Leeuwenhoek's designs were very basic. The body of the microscope was a single lens mounted in a tiny hole on a brass plate. The specimen was then mounted on a sharp point that sticks up in front of the lens. It's position and focus could be adjusted by turning the two screws.

The entire instrument was about 3 to 4 inches long and had to be held up close to the eye, requiring good lighting and great patience to use.

nika2105 [10]3 years ago

4 0

Electron microscope- i hope this helps plz mark as brainliest and god bless

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Suppose a couple has come to see you to discuss the probability of their children having cystic fibrosis (CF). CF is known to be

m_a_m_a [10]

Answer:

The children that the couple may have a 25% chance of having cystic fibrosis and 75% chance of being carriers for the CF gene

Explanation:

We know that both parents are in the same situation. Let's start for example with the mother. She has one parent and one sibling with cystic fibrosis (CF). So, supposing that the allele of the gene that causes the disease is "f", as the disease is autosomal recessive, both, the parent and the sibling have the genotype ff.

Also, knowing that the other parent has a normal phenotype, but the sibling has CF, we deduce that the other parent of the mother must have a Ff.

So, despite the mother's phenotype is normal, her genotype is Ff (see the Punnett square 1) Couple's parents in the attached image). In other words, she is a carrier for the CF gene.

As the parents' situation is analogous, we can deduce that the father also has a genotype Ff and is also a carrier for the CF gene.

Now, if we look at the Punnett square for them (see the square 2) Couple in the attached image), we see that all their children will always have at least one copy of the CF allele, f.

More specifically, their children have 25% chance of having cystic fibrosis and 75% chance of having a normal phenotype but being carriers of the CF gene.