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Fantom [35]
3 years ago
11

6.2 independent practice

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer: ?????

Step-by-step explanation:

xz_007 [3.2K]3 years ago
3 0
...? This isn’t a question..
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Sid starts with savings of £13
MAVERICK [17]

Answer:

The savings of Sid and Tim will be in 17:9 in 6 weeks.

Step-by-step explanation:

Initial savings of Sid = £ 13

Initial savings of Tim = £ 0

For each successive week Sid saved = £ 3.5

For each successive week Tim saved = £ 3

Let us assume that after "x weeks" the amounts of Sid and Tim are in ratio 17:9.

If Sid saves £ 3.5 in one week, in x weeks he will £ 3.5x. Since he had £ 13 initially, total amount he would have in x weeks will be £ (13 + 3.5x)

If Time saves £ 3 one week, in x weeks he will save £ 3x. Since, he didn't have any money initially, in x weeks he would have saved £ 3x

The ratio of their savings in x weeks would be 17:9

So,

Sid's saving : Tim's saving = 17 : 9

Using the values of expressions, we get:

13+3.5x:3x=17:9\\\\\frac{13+3.5x}{3x}=\frac{17}{9}\\\\ 9(13+3.5x)=17(3x)\\\\ 117+31.5x=51x\\\\ 117=51x-31.5x\\\\ 117=19.5x\\\\ x=\frac{117}{19.5}\\\\ x=6

This means, the savings of Sid and Tim will be in 17:9 in 6 weeks.

5 0
4 years ago
How many zero arin the product of any whole. number less than 10 and 500
Stolb23 [73]

Answer:

Hay un máximo de tres ceros en el producto de un número distinto de cero cero menor que 10 y 500

Para poder ver esto, la forma más fácil para resolver este problema es multiplicar todos los números entre 1 y 9 por 500, es decir:

01*500 = 500

2*500 = 1.000

3*500 = 1.500

4*500 = 2.000

5*500 = 2.500

6*500 = 3.000

7*500 = 3.500

8*500 = 4.000

9*500 = 4.500

Como vemos, si multiplicamos a 500 por cualquier número par, entonces obtenemos un número con tres ceros, mientras que si este es impar solamente obtenemos dos ceros

dame coronaa

7 0
3 years ago
Read 2 more answers
If (a,b) is an ordered pair for x-y=5, is (b,a) also a solution?
alina1380 [7]
The answer is no. Because solution (a,b) means x=a, y=b.and we have a-b=5.  And (b,a) would mean x=b and y=a but then x-y=b-a=-(a-b)=-5≠5. So  the pair (b,a) is not a solution.


5 0
4 years ago
Which pair of values could NOT be the roots of a quadratic polynomial?
DENIUS [597]

Answer:

Part c

Step-by-step explanation:

In quadratic equations of real coefficients, the complex roots always occur in conjugate bases. It means, if, 2 + 3i is one of the roots and then the second root must be 2 - 3i.

7 0
3 years ago
Read 2 more answers
What expression shows the relationship between the value of any term and n, its position in the sequence for the given sequence?
san4es73 [151]

Answer:

a(n)=3+(n-1)2

Step-by-step explanation:

a(n)=3+(n-1)2

arithmetic sequence

5 0
3 years ago
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