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Ksenya-84 [330]
3 years ago
15

a stack of congruent blocks, piled one on top of the other, is 4/5 foot high. Each block is 1/10 foot tall. How many blocks are

in the stack?
Mathematics
1 answer:
kvasek [131]3 years ago
6 0
8 blocks because 2/10=1/5 so if they total 4/5 then 2/10+2/10+2/10+2/10=8/10=4/5
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Step-by-step explanation:

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Consider the sequence: 11, 21, 31, …, … , … What is the nth term of this sequence ?
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−6x+14<−28 OR 9x+15≤−12
Serhud [2]

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

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3 years ago
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About 95% of scores fall in this range
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