Solve the following inequality. 3x + 5 < 6x - 1
2 answers:
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The question is incomplete. Here is the complete question:
Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.
A.
B.
C.
D.
Answer:
A.
D.
Step-by-step explanation:
Given:
The range is greater than or equal to 1 or less than or equal to -1.
The given choices are:
Choice A:
We know that, the
The range of is from -1 to 1 given as [-1, 1]. So,
Therefore, on removing the absolute sign, we rewrite the secant function as:
Therefore, the range of is all real numbers greater than or equal to 1 or less than or equal to-1.
Choice B:
We know that, the range of tangent function is all real numbers. So, choice B is incorrect.
Choice C:
We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.
Choice D:
We know that, the
The range of is from -1 to 1 given as [-1, 1]. So,
Therefore, on removing the absolute sign, we rewrite the cosecant function as:
Therefore, the range of is all real numbers greater than or equal to 1 or less than or equal to-1.