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dangina [55]
3 years ago
11

The graph of the function f is shown. f(0) = A) f(-1) B) f(2) C) f(3) D) f(4)

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

GG?

Step-by-step explanation:

aalyn [17]3 years ago
5 0

f(0)  means x = 0

so when x = 0, y = -5

and when x = 4, f(4) is also equal -5 (y = -5)

so f(0) = f(4) = -5

Answer

D) f(4)

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Read 2 more answers
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\bf f(x)=log\left( \cfrac{x}{8} \right)\\\\&#10;-----------------------------\\\\&#10;\textit{x-intercept, setting f(x)=0}&#10;\\\\&#10;0=log\left( \cfrac{x}{8} \right)\implies 0=log(x)-log(8)\implies log(8)=log(x)&#10;\\\\&#10;8=x\\\\&#10;-----------------------------

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----------------------------------------------------------------------------------------------




now on 2)

\bf f(x)=\cfrac{3}{x^4}   if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,

in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0


vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at  x^4=0\implies x=0  or the y-axis

----------------------------------------------------------------------------------------------


now on 3)

\bf f(x)=\cfrac{1}{x}


now, let's see some transformations templates

\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\mathbb{R}^{{{  B}}x+{{  C}}}+{{  D}}&#10;\end{array}


\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}&#10;\end{array}


now, let's take a peek at g(x)

\bf \begin{array}{lcllll}&#10;g(x)=&-&\cfrac{1}{x}&+3\\&#10;&\uparrow &&\uparrow \\&#10;&\textit{upside down}&&&#10;\begin{array}{llll}&#10;\textit{vertical shift up}\\&#10;\textit{by 3 units}&#10;\end{array}&#10;\end{array}


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