Ask question

Ask question

All categories

2 years ago

11

Analyze the graph and identify some factors that may contribute to the rotifer population leveling off in the absence of water f

leas. Explain your answer in 1–2 sentences
25 POINTS!

1 answer:

liraira [26]2 years ago

3 0

Answer:

Step-by-step explanation:

Firstly, we should begin to know what leveling off is.

Leveling off- to stay the same after a period of increase

Nearing the end of the graph you can see there is no continuous increase for the rotifers. That can be explained by carrying capacity. The flask has limited space.

You might be interested in

1. Who authored the web page? How do you know?

Deffense [45]

I can’t see where someone authored this web pages and no I don’t know unless if you’ve shown me it.

5 0

3 years ago

Read 2 more answers

If f(x) =3x-5 them find values of f(3) and f(-7). please explain step by step

LenKa [72]

Answer:

f(3) = 4

f(-7) = -26

Step-by-step explanation:

Hi there!

$f(x) =3x-5$

To find f(3), replace every x with 3:

$f(3) =3(3)-5\\f(3) =9-5\\f(3) =4$

Therefore, f(3)=4.

$f(x) =3x-5$

To find f(-7), replace every x with -7:

$f(-7) =3(-7)-5\\f(-7) =-21-5\\f(-7) =-26$

Therefore, f(-7)=-26.

I hope this helps!

8 0

2 years ago

Insert parentheses to make the statement true <br> 21-8-6=7

Advocard [28]

(21-8)-6=7

and that's it

5 0

3 years ago

BRAINLIEST <br> Please help ASAP and leave a small explanation :)

Andreas93 [3]

1 and 8 are because they are alternate exterior angles

3 0

3 years ago

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours:

$t_{T} = t_{R}+t_{H}+t_{W}$

If Keenan runs and walks at constant speed, then equation above can be expanded:

$t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}$

Where:

$x_{R}$ , $x_{W}$ - Run and walk distances, measured in miles.

$v_{R}$ , $v_{W}$ - Run and walk speeds, measured in miles per hour.

Given that $x_{R}=x_{W} = 2.5\,mi$ , $v_{R} = 6\,\frac{mi}{h}$ , $v_{W} = 4\,\frac{mi}{h}$ and $t_{H} = 0.75\,h$ , the total time is:

$t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }$

$t_{T} = 1.792\,h$ ( $1\,h\,48\,m$ )

Kennan will be from home approximately an hour and 48 minutes.

7 0

3 years ago