How do you find the sigma of the x and y values? Do you do it like a partial derivative?
1 answer:
Answer:
Step-by-step explanation:
Sample size of 8 infants were taken and their birth lengths in inches recorded and also 6 months lengths.
If x is length at birth time, and y 6 month length
we have as per table below.
x y x^2 y^2 xy
1 19.75 25.5 390.0625 650.25 503.625
2 20.5 26.25 420.25 689.0625 538.125
3 19 25 361 625 475
4 21 26.75 441 715.5625 561.75
5 19 25.75 361 663.0625 489.25
6 18.5 25.25 342.25 637.5625 467.125
7 20.25 27 410.0625 729 546.75
8 20 26.5 400 702.25 530
Total 158 208 3125.625 5411.75 4111.625
SSxx = 3125.625 and SSyy = 5411.75
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Answer:
- <u>Option B. 59%</u>
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.