Question

Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula?

Answer 1

The correct answer is:

$x=\frac{1\pm \sqrt{(-1)^2-4(1)(-2)}}{2(1)}$

Explanation:

The Quadratic Formula is

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$,

where a, b and c are the coefficients of a quadratic equation written in standard form, or 0=ax²+bx+c.

This means that first, we need to make our equation equal 0.

We have

-2 = -x + x² - 4

To make this equal 0, we must cancel the -2.  We do this by adding 2:

-2+2 = -x + x² - 4 + 2

0 = -x + x² - 2

Now we write this in standard form.  This means the x² term must come first, then the x term, then the constant:

0 = x²-x-2

This makes a = 1, b = -1 and c = -2.  We then plug this into the quadratic formula.

Answer 2

Answer:

D.

Step-by-step explanation:

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