The pieces are 2.5 and 7.5 the 7.5 is the piece that is 3 times the length of the first one
Well, given that a quarter equals 5 nickels, we can reason that, in order to get 12 coins, we would have to get 10 nickels (equals 50 cents) and 2 quarters (the other 50 cents, to make a dollar).
You didn't say whether you needed this expressed in a mathematical formula, but knowing the answer already, it shouldn't be hard to come up with one if necessary.
Hope this helps.
The measure of a central angle is equal to measure of a minor arc. That makes m<GEH=17x+12. By the Vertical Angles Theorem, m<GEH and m<IEF are equal to each other (m<GEH=17x+12=m<IEF). By the same theorem, m<FEG and m<IEH are also equal (m<FEG=8x-7=m<IEH). The angles in a circle must all add up to 360 degrees, 2(17x+12)+2(8x-7)=360. Solve for x, then plug x into the equation for m<IEF.
Hope this helps!
Step-by-step explanation:
the length of the third side could be 6
As in order to form a triangle The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
so Here
8 + 3 > 6
11 > 6 ( True) ✔
8+ 6 > 3
14 > 3 ( True) ✔
6 + 3 > 8
9 > 8 ( True) ✔
Hope it will help you :)
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
