Answer:
The product of the other two zeros is c
Step-by-step explanation:
Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:
sum of the roots = α + β + γ = -a
-1 + β + γ = -a
β + γ = -a + 1
αβ + αγ + βγ = b
-1(β) + (-1)γ + βγ = b
-β -γ + βγ = b
Also, the product of the zeros is equal to -c, hence:
αβγ = -c
-1(βγ) = -c
βγ = c
Hence the product of the other two zeros is c
Answer:
B
Step-by-step explanation:
To complete the question, here are the answer choices:
<em>A) =A1*A2*A3*A4
</em>
<em>B) =A1*A2+A3+A1*A4
</em>
<em>C) =A1*(A2+A3+A1)*A4
</em>
<em>D) =A1*A2+(A3+A1)*A4</em>
<em />
We first need to multiply A1 and A2, this will give weight of passengers.
To get weight of luggage, we multiply A1 and A4.
We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.
So we will get
A1*A2 + A1*A4 + A3
This is given in a different order in Option B. Hence, option B is right.
Answer:
Step-by-step explanation:
First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items
F(x) = x^3-3x^2+0x+0
We have to divide this by x-2
Leading terms in the dividend and divisor are
x^3 and x
Hence quotient I term would be x^3/x=x^2
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
Multiply x-2 by x square and write below the term and subtract
We get
x-2) x^3-3x^2+0x+0(x^2
x^3-2x^2
---------------
-x^2+0x
Again take the leading terms and find quotient is –x
x-2) x^3-3x^2+0x+0(x^2-x
x^3-2x^2
---------------
-x^2+0x
-x^2-2x
Subtract to get 2x +0 as remainder.
x-2) x^3-3x^2+0x+0(x^2-x-2
x^3-2x^2
---------------
-x^2+0x
-x^2+2x
-------------
-2x-0
-2x+4
------------------
-4
Thus remainder is -4 and quotient is x^2-x-2
Answer:
y=-2x-4
Step-by-step explanation:
