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Ad libitum [116K]
3 years ago
6

you invest 1000 in an account that pays simple interest of 6% for 30 years what. How much money will you have in 30 years

Mathematics
2 answers:
Genrish500 [490]3 years ago
6 0
A = P(1+rt)
A = 1000(1+.06x30) = 2800
Scorpion4ik [409]3 years ago
3 0
I=PRT
Interest=Principal times Rate times Time

principal=amount invested
r=rate in decimal
t=time in years

so
P=1000
r=6$=0.06
t=30yr

I=(1000)(0.06)(30)
I=1800 interest

you will have 1000+1800 or $2800 in 30 years
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Step-by-step explanation:

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60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10).  The only of these that sum to -19 are -4 and -15.  This means we will split up -19x into -4x and -15x:

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Next we group the first two terms and the last two terms:

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-5(3x-4)

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