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Radda [10]
3 years ago
12

Phil wants to add a new video card, and he is sure the power supply is sufficient to run the new video card. But when he tries t

o locate the power connector for the new video card, he does not find a 6-pin PCI-E power connector. He has several extra cables for hard drive power cables from his power supply that he is not using.
​

What is the least expensive way for Phil to power his video card?
Computers and Technology
1 answer:
pshichka [43]3 years ago
4 0

Answer:

Using a SATA to a 6 pin PCI-E adapter.

Explanation:

sometimes you may feel the need to make some upgrades to your computer, video cards are options where an upgrade is made, a 6 Pin PCI-E adapter is 6 pins 12V power adapter used to power a video card where their slots cannot provide them with enough power they require. in a situation where the card requires a lot of power than the slot can provide, 6 pins PCI-E adapter is a very good option.

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Consider a pipelined processor with just one level of cache. assume that in the absence of memory delays, the baseline cpi of th
babunello [35]

Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.

8 0
2 years ago
While a threat intelligence analyst was researching an indicator of compromise on a search engine, the web proxy generated an al
inna [77]

Answer: the corret answer C. The analyst has prefetch enabled on the browser in use.

Explanation:

The analyst has like an indicator which is prefetch enabled on the browser in use.

7 0
2 years ago
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
2 years ago
how could environmental and energy problem Kenya faces as far computer installations are concerned be avoided​
ipn [44]

The environmental and energy problem Kenya faces as far computer installations are concerned can be avoided​ by

  • Knowing and finding out the key aspect of ICT strength.
  • Create an holistic judgements in the assessment of ICT capability. Promote the use of solar power.

<h3>How can we overcome ICT challenges?</h3>

There are a lot of Energy Challenges in terms of ICT  in Kenyan and it is good the government and the people work towards energy in terms of sustainable ICT.

Therefore, The environmental and energy problem Kenya faces as far computer installations are concerned can be avoided​ by

  • Knowing and finding out the key aspect of ICT strength.
  • Create an holistic judgements in the assessment of ICT capability. Promote the use of solar power.

Learn more about computer installations from

brainly.com/question/11430725

#SPJ1

7 0
1 year ago
I hate school...............
butalik [34]

Answer:

Check your email.

Explanation:

8 0
2 years ago
Read 2 more answers
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