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Radda [10]
3 years ago
12

Phil wants to add a new video card, and he is sure the power supply is sufficient to run the new video card. But when he tries t

o locate the power connector for the new video card, he does not find a 6-pin PCI-E power connector. He has several extra cables for hard drive power cables from his power supply that he is not using.
​

What is the least expensive way for Phil to power his video card?
Computers and Technology
1 answer:
pshichka [43]3 years ago
4 0

Answer:

Using a SATA to a 6 pin PCI-E adapter.

Explanation:

sometimes you may feel the need to make some upgrades to your computer, video cards are options where an upgrade is made, a 6 Pin PCI-E adapter is 6 pins 12V power adapter used to power a video card where their slots cannot provide them with enough power they require. in a situation where the card requires a lot of power than the slot can provide, 6 pins PCI-E adapter is a very good option.

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Yani cnm bu senin kararin istegidiin gibi davran Basarilar
8 0
3 years ago
When you print ____, the presentation is printed with one or more slides on each piece of paper?
Artist 52 [7]
When you print handouts, the presentation is printed with one or more slides on each piece of paper. When you print handouts, it's best to have the presentation printed on them for those who can not view the presentation clearly to follow along with. This also serves as a great tool for people who missed the presentation to receive a handout later or for those there to take home and review. 
8 0
3 years ago
Write a program using integers userNum and x as input, and output userNum divided by x four times. Ex: If the input is: 2000 2
STatiana [176]

Answer:

// here is code in c++.

// include header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variables to read input

   int userNum,x;

   cout<<"enter the value of userNum and x :";

   // read the input from user

   cin>>userNum>>x;

   // divide the userNum with x 4 times

   for(int a=0;a<4;a++)

   {

       userNum=userNum/x;

       cout<<userNum<<" ";

   }

       cout<<endl;

return 0;

}

Explanation:

Declare two variables "userNum" and "x". Read the value of these. Run a for loop 4 time and divide the "userNum" with "x" and print  the value of "userNum".

<u>Output:</u>

enter the value of userNum and x :2000 2                                                                                  

1000 500 250 125  

3 0
3 years ago
When you save something to the Desktop on a school computer, what drive letter will it save to
Natali [406]

When you save something to the Desktop on a school computer, the drive letter it will save to the C drive.

<h3>What is a C drive?</h3>

C drive is that part of the computer that contains the operating system and files of the system. The files on which we worked are saved on the C drive of the system.

This is a type of hard drive. The work we have done on the system is automatically saved on the drive. We can easily find the C drive on the computer's file explorer. It automatically saved the data, but you can save manually the data of the D drive.

Thus, the drive letter it will save to the C drive.

To learn more about C drive, refer to the link:

brainly.com/question/2619161

#SPJ1

4 0
2 years ago
Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and events (like the 10 or 90
Norma-Jean [14]

Answer:

The C code for the problem is given below

Explanation:

#include <stdio.h>

int main() {

   int highwayNumber;

   int primaryNumber;

   scanf("%d", &highwayNumber);

   if (highwayNumber >= 1 && highwayNumber <= 999) {

       if (highwayNumber <= 99) {

           if (highwayNumber % 2 == 0) {

               printf("I-%d is primary, going east/west.\n", highwayNumber);

           } else {

               printf("I-%d is primary, going north/south.\n", highwayNumber);

           }

       } else {

           primaryNumber = highwayNumber;

           highwayNumber %= 100;

           if (highwayNumber % 2 == 0) {

               printf("I-%d is auxiliary, serving the I-%d, going east/west.\n", primaryNumber, highwayNumber);

           } else {

               printf("I-%d is auxiliary, serving the I-%d, going north/south.\n", primaryNumber, highwayNumber);

           }

       }

   } else {

       printf("%d is not a valid interstate highway number.\n", highwayNumber);

   }

   return 0;

}

4 0
3 years ago
Read 2 more answers
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