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3 years ago

Solve for x. Enter your answer below as an improper fraction in lowest terms, using the slash ( / ) as the fraction bar.

Mathematics

1 answer:

anastassius [24]3 years ago

4 0

If x - 8 8/9 = 6/7, we can add 8 8/9 to each side to figure out what x is equal to.

x = 8 8/9 + 6/7

Now we find the LCD of 7 and 9 (63)

x = 8 56/63 + 54/63

Now we convert 8 into something over 63

x = $\frac{8*63+56+54}{63}$

x = $\frac{614}{63}$

Since these two numbers don't share any common factor, the answer for our question is x = $\frac{614}{63}$

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spin [16.1K]

Answer:

4/25

Step-by-step explanation:

8/10 = 4/5

2/10 = 1/5

We can multiply these 2 events because they do not depend on each other.

1/5* 4/5 = 4/25

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3 years ago

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daser333 [38]

Answer:

The answer is D

Step-by-step explanation:

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3 years ago

State the properties of the Normal Probability Distribution<br> in own word.

dybincka [34]

Answer:

he mean, mode and median are all equal. The curve is symmetric at the center (i.e. around the mean, μ). Exactly half of the values are to the left of center and exactly half the values are to the right. The total area under the curve is 1.

Step-by-step explanation:

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3 years ago

Find the area of the composite figure.

MArishka [77]

2 × 6 = 12

12 ÷ 2 = 6

2 × 14 = 28

10 × 20 = 200

6 + 28 + 200 = 234

7 0

3 years ago

Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi

Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

$h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6$

And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

3 0

3 years ago