All categories

2 years ago

What element has a total of 3 p-sublevel electrons?

Chemistry

1 answer:

den301095 [7]2 years ago

8 0

Elements with three p-electrons....

That would be N, P, As, Sb, and Bi -- elements in group 15

For example, energy diagram showing "empty" orbitals up through the 3p.

.....3p __ __ __

3s __

.....2p __ __ __

2s __

1s __

Energy diagram of phosphorous showing three unpaired electrons in 3p-sublevel

.....3p ↑_ ↑_ ↑_

3s ↑↓

.....2p ↑↓ ↑↓ ↑↓

2s ↑↓

1s ↑↓

According to Hund's rule, the electrons singly occupy the p-orbitals, and all have the same spin.

You might be interested in

A student attempted to identify an unknown compound by the method used in the experiment. She found that when she heated the sam

yanalaym [24]

Na2CO3 + 2Cl- ⇒ 2NaCl + CO3^-2

1 mole of Na2CO3 = 106 g 
2 moles of NaCl = 2 x 58.4
= 116.8 g
Na2CO3 would increase by 116.8 / 106 = 1.10 to form 2NaCl.
0.4862 g x 1.10 = 0.515 grams of NaCl.

K2CO3 + 2Cl- ⇒ 2KCl + CO3^-2
1 mole of K2CO3 = 138.2 g 
2 moles of KCl = 149.1 

K2CO3 would increase by 149.1 /138.2 = 1.079 to form 2KCl

 0.4862 x 1.079 = 0.5246 g

3 0

2 years ago

Read 2 more answers

at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were

Nataly [62]

Answer: The percent change in volume will be 25 %

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1$

Putting values in above equation, we get:

$\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L$

Percent change of volume = $\frac{\text{Change in volume}}{\text{Initial volume}}\times 100$

Percent change of volume = $\frac{(2-1.5)}{2}\times 100=25\%$

Hence, the percent change in volume will be 25 %

5 0

2 years ago

(a) the characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustio

ella [17]

By stoichiometry and assume that:

CxH2xOy + zO2 -> xCO2 + xH2O

CO2: 9.48/44 = 0.215 mmol
H2O: 3.87/18 = 0.215 mmol
mass of C = 0.215 * 12 = 2.58 mg
mass of H = 0.215 * 2 * 1 = 0.43 mg
mass of O in ethylbutyrate = 4.17 - 2.58 - 0.43 = 1.11 mg
So C/O = 2.58/1.11 ≈ 3

Thus we have C3H6O

8 0

2 years ago

Read 2 more answers

Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe

Illusion [34]

Answer:

a. Kp=1.4

$P_{A}=0.2215 atm$

$P_{B}=0.556 atm$

b.Kp=2.0 * 10^-4

$P_{A}=0.495atm$

$P_{B}=0.00995 atm$

c.Kp=2.0 * 10^5

$P_{A}=5*10^{-6}atm$

$P_{B}=0.9999 atm$

Explanation:

For the reaction

A(g)⇌2B(g)

Kp is defined as:

$Kp=\frac{(P_{B})^{2}}{P_{A}}$

The conditions in the system are:

A B

initial 0 1 atm

equilibrium x 1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.

Replacing these values in the expression for Kp we get:

$Kp=\frac{(1-2x)^{2}}{x}$