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horrorfan [7]
3 years ago
9

Cyclopropane, C3H6, is converted to its isomer propylene, CH2=CHCH3, when heated. The rate law is first order in cyclopropane, a

nd the rate constant is 6.0 × 10−4/s at 500°C. If the initial concentration of cy- clopropane is 0.0226 mol/L, what is the concentration after 525 s?
Chemistry
1 answer:
sukhopar [10]3 years ago
6 0

Answer: 0.011 M

Explanation:

C_3H_6\rightarrrow CH_2=CH-CH_3

Rate=k[C_3H_6]^1

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 6.0\times 10^{-4}\text{s}^{-1}

t = time taken   = 525 sec

a = initial amount of the reactant  = 0.0226 mol/L

a - x = amount left = ?

Now put all the given values in above equation, we get

525=\frac{2.303}{6.0\times 10^{-4}}\log\frac{0.0226}{(a-x)}

(a-x)=0.011mol/L

Thus the concentration after 525 s is 0.011 mol/L.

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I, ii is the answer
7 0
2 years ago
What is the mass of 2.3 moles of aluminum (Al)?
tangare [24]
2.3 mols of Al*26.98 molar mass of Al=62.054g
3 0
3 years ago
You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid
Art [367]

Answer:

V_1=2.49mL

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

n_{HI}=n_{HI}

One could apply the following equality in terms of molarity:

V_1M_1=V_2M_2

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL

Best regards.

5 0
3 years ago
How many hydrogen atoms are in 5.20 mol of ammonium sulfide?
Fofino [41]
1) Molecular formula of ammonium sulfide

(NH4)2 S

2) That means that there are 2*4 = 8 atoms of hydrogen in each molecule of ammoium sulfide, so in 5.20 mol of molecules will be 8 * 5.20 mol = 41.6 moles of atoms of hydrogen

3) To pass to number of atoms multiply by Avogadro's number: 6.022 * 10^23

41.6 moles * 6.022 * 10^23 atoms / mol = 250.5 * 10^23 = 2.50 * 10^25 atoms

Answer: 2.50 * 10^25
8 0
3 years ago
4. a compound called pyrene has the empirical formula c8h5. when 4.04 g of pyrene is dissolved in 10.00 g of benzene, the boilin
e-lub [12.9K]

The molecular mass of pyrene is 204.4 g/mol.

From;

ΔT = Kb m i

Where;

  • ΔT = boiling point elevation
  • Kb = boiling point constant
  • m = molality
  • i = Van't Hoff factor

Since the compound is molecular; i = 1

The number of moles of pyrene = 4.04 g/MM

Where; MM = molar mass of pyrene

molality = number of moles of pyrene/mass of solvent in Kg

The mass of solvent = 10 g or 0.01 Kg

molality =  4.04 g/MM/0.01

ΔT = Boiling point of solution - Boiling point of pure solvent

ΔT = 85.1°C - 80.1°C

ΔT = 5°C

5 = 2.53 × 4.04 g/MM/0.01 × 1

5 = 10.22 × 1/0.01 MM

0.05MM = 10.22

MM= 10.22/0.05

MM= 204.4 g/mol

Learn more: brainly.com/question/2292439

3 0
2 years ago
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