a rock that originally had a mass of 1.00g of uranium_238 now only has .125g left. how old is the rock if the half life of urani
1 answer:
You might be interested in
Answer:
See explanation and image attached
Explanation:
Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.
Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.
Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.
The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.
Answer:
b. 10 mL
Explanation:
First we <u>calculate the amount of H⁺ moles in the acid</u>:
- pH = -log [H⁺]
- [H⁺] =
- [H⁺] = 10⁻⁵ = 1x10⁻⁵M
100 mL ⇒ 100 / 1000 = 0.100 L
- 1x10⁻⁵M * 0.100 L = 1x10⁻⁶ mol H⁺
In order to have a neutral solution we would need the same amount of OH⁻ moles.
We can use the pOH value of the strong base:
- pOH = 14 - pH
- pOH = 14 - 10 = 4
Then we <u>calculate the molar concentration of the OH⁻ species in the basic solution</u>:
- pOH = -log [OH⁻]
- [OH⁻] =
= 1x10⁻⁴ M
If we use 10 mL of the basic solution the number of OH⁻ would be:
10 mL ⇒ 10 / 1000 = 0.010 L
- 1x10⁻⁴ M * 0.010 L = 1x10⁻⁶ mol OH⁻
It would be equal to the moles of H⁺ so the answer is b.
<u>Answer: </u>
<u>For 1:</u> 3.3 moles of oxygen gas is required.
<u>For 2:</u> 14 moles of hydrogen gas is required.
<u>For 3:</u> 1.5 moles of oxygen gas is required.
<u>Explanation:</u>
The chemical reaction of oxygen and hydrogen to form water follows:
- <u>For 1:</u> When 6.6 moles of
is reacted.
By Stoichiometry of the above reaction:
2 moles of hydrogen gas reacts with 1 mole of oxygen gas.
So, 6.6 moles of hydrogen gas will react with = of oxygen gas.
Hence, 3.3 moles of oxygen gas is required.
- <u>For 2:</u> When 7.0 moles of
is reacted.
By Stoichiometry of the above reaction:
1 mole of oxygen gas reacts with 2 moles of hydrogen gas.
So, 7 moles of oxygen gas will react with = of hydrogen gas.
Hence, 14 moles of hydrogen gas is required.
- <u>For 3:</u> When 3.0 moles of
is formed.
By Stoichiometry of the above reaction:
2 moles of water is formed from 1 mole of oxygen gas.
So, 3.0 moles of water will be formed from = of oxygen gas.
Hence, 1.5 moles of oxygen gas is required.