Answer:
Total pressure = 4.57 atm
Explanation:
Given data:
Partial pressure of nitrogen = 1.3 atm
Partial pressure of oxygen = 1824 mmHg
Partial pressure of carbon dioxide = 247 torr
Partial pressure of argon = 0.015 atm
Partial pressure of water vapor = 53.69 kpa
Total pressure = ?
Solution:
First of all we convert the units other into atm.
Partial pressure of oxygen = 1824 mmHg / 760 = 2.4 atm
Partial pressure of carbon dioxide = 247 torr / 760 = 0.325 atm
Partial pressure of water vapor = 53.69 kpa / 101 = 0.53 atm
Total pressure = Partial pressure of N + Partial pressure of O + Partial pressure of CO₂ + Partial pressure of Ar + Partial pressure of water vapor
Total pressure = 1.3 atm + 2.4 atm + 0.325 atm + 0.015 atm + 0.53 atm
Total pressure = 4.57 atm
Answer: The final temperature of both the weight and the water at thermal equilibrium is
.
Explanation:
The given data is as follows.
mass = 7.62 g, 
Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.
q =
= 
Now, heat gained by lead will be calculated as follows.
q =
=
According to the given situation,
Heat lost = Heat gained
= 
T = 
Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is
.
Answer:
It would be 25% because each equals 25%.
Explanation:
There is 4 "shapes" each can equal 25 because 25+25+25+25=100.
Answer:
Explanation:
From the information given:
Feed F = 150.0 kmol/hr
The saturated liquid mixture of the distillation column is
= 30%
Reflux ration = 2.0%
methanol distillate mole fraction
= 0.990
recovery of methanol in the distillate = 97.0%
The distillate flow rate D can be determined by using the formula;

D = 0.97 × 150 × 0.3
D = 43.65 kmol/h
The bottom flow rate Balance B on the column is:
F = D + B
150 = 43.65 + B
B = ( 150 - 43.65 )kmol/h
B = 106.35 kmol/h
The methanol mole fraction in the bottom
can be computed by using the formula:

150(0.3) = 43.65(0.999) + 106.3(
)
45 = 43.60635 + 106.3(
)
45 - 43.60635 = 106.3(
)
1.39365 = 106.3(
)
= 1.39365 / 106.3
= 0.013
the fractional recovery of water in the bottoms f is calculated as:



f = 0.99969