478(900) + 478(95)
Hope this helps!
Answer:
The money she will end up earning in interest on the cd = $11,352.90
Step-by-step explanation:
The formula for getting the accumulated amount(compounded) is;
Where
A = Accumulated amount
P = principle (deposit)
r = interest rate and
n = no of times interest applied per time period.
The interest is compounded quarterly so in one year it will be 4 times
In 5 years
n = (5×4)-3 = 17 (as she will withdraw 3 month before the completion of five years)
A = 
^17
= 7100( 1 + 0.028)^17
= 7100(1.028)^17
= 7100 * 1.599
= 11,352.90
Therefore the money she will end up earning in interest on the cd = $11,352.90
40 wpm. Because 160/4=40.
I hope that helped!
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>4x - 3y + z = - 10</span>
<span>-4x - 2y - 6z = 0</span>
<span>-5y - 5z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>- x + 2y - 5z = 17</span>
<span>2x + y + 3z = 0</span>
<span>-2x + 4y - 10z = 34</span>
<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span>
<span>5y - 7z = 34</span>
<span>-12z = 24</span>
which is , <span>z = - 2</span>
<span>-5y - 5(- 2) = - 10</span>
<span>-5y = - 20</span>
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span>
<span>- x + 2(4) - 5(- 2) = 17</span>
<span>- x + 18 = 17</span>
<span>- x = - 1</span>
<span>x = 1</span>
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span>
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>
</span>
-27 divided by 9 = -3, 4 x -6 = -24, 12 x -10 = -120, -45 divided by -5 = 9, 7 x -3 = -21, 72 divided by -8 = -9, 64 dibided by 8 is 8, and -8 x 6 is -48. good luck!! ^_^
