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2 years ago

The number of hours of television watched per day by a sample of 28 people is given below:

Mathematics

1 answer:

Paha777 [63]2 years ago

5 0

61% of the people watch no more than 4 hours of television per day.

Step-by-step explanation:

Stack data in each row.
Sort it from lowest to highest.
Maximum is the 9 and minimum is 0.
Grouped Frequency first is to find the classes should be 5-15 classes.
Width of the class should be max-min/classes result 1.28 need roundup.
Width of the classes is 2. first to find cumulative frequency.
Percentage frequency of all the width of the classes.
Cumulative percentage 4 hours per day comes to 61%.
The result is 61%.

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2 years ago

Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.

statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that $p = \frac{231}{361} = 0.6399$

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095$

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

$E = -31*0.4095 + 21*0.5905 = -0.29$

The expected value of the proposition is of -0.29.

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2 years ago

Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n

ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0

2 years ago

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