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allsm [11]
3 years ago
10

experiment consists of rolling three fair dice --- a red die, a blue die, and a white die --- and recording the number rolled on

each die. Assume that the dice are fair, so that all outcomes are equally likely. What is the probability that the sum of the dice rolled is 6?
Mathematics
1 answer:
nalin [4]3 years ago
8 0
The possible permutations are 6P3 which is 120. Out of those there are 7 ways to get 6 with three dice. So P(6)=7/120
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balu736 [363]

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7x + 2y = 1

First isolate one of the variables (x or y) in one of the equations.

Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.

3x + y = 3      Subtract 3x on both sides

3x - 3x + y = 3 - 3x

y = 3 - 3x


7x + 2y = 1

7x + 2(3 - 3x) = 1     [since y = 3 - 3x, you can substitute (3-3x) for "y"]

Multiply/distribute 2 into (3 - 3x)

7x + (3(2) - 3x(2)) = 1

7x + 6 - 6x = 1

x + 6 = 1     Subtract 6 on both sides

x = -5


Now that you know "x", substitute it into one of the equations (I will do both)

3x + y = 3

3(-5) + y = 3       [since x = -5, you can plug in -5 for "x"]

-15 + y = 3    Add 15 on both sides

y = 18


7x + 2y = 1

7(-5) + 2y = 1

-35 + 2y = 1     Add 35 on both sides

2y = 36     Divide 2 on both sides

y = 18


x = -5, y = 18  or  (-5, 18)

5 0
3 years ago
Maths giving 10 point asap 1 question only<br><br><br><br><br><br>Find the value of P​
timurjin [86]

Answer:

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Step-by-step explanation:

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ahrayia [7]

Answer:

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zhuklara [117]
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