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Charra [1.4K]
3 years ago
9

What is the value of the product (3-2i)(3+2i)?

Mathematics
2 answers:
blondinia [14]3 years ago
8 0
(3 - 2i)(3 + 2i)
(6 + 6i) + (-6i - 4i^2)
(4i^2 - 6i)
+ (6i + 6)
(4i^2 + 6)
Helga [31]3 years ago
5 0

Answer:

13

Step-by-step explanation:

(3-2i)(3+2i) = 9  + 6i - 6i - 4i^2

9 - 4i^2

9 + 4 = 13

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Keira keeps a record of the number of songs she downloads each months
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Good for Keira. Is there a question that goes along with this?
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Solve the equation -3 + 1/2n = 1/2 (-n + 14) in two different ways.
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Answer:

Step-by-step explanation:

-3 + 1/2n = 1/2 (-n + 14)

distribute

-3 + 1/2n = -1/2n + 7

                 -1/2n

cancel out -1/2n

-3 = n + 7

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4 0
2 years ago
The airline that Vince is using has a
emmainna [20.7K]

Answer:

Each bag must NOT exceed 62 inches (157.48 centimeters) in overall dimensions (length + width + height) and CANNOT exceed 70 pounds (31.75 kg). Overweight bag fees will apply to bags weighing over 50 pounds (22.73 kg).

Dominican Republic: 18% of baggage fee

Colombia: 16% of baggage fee

Saint Lucia: 7.5% of baggage fee

Barbados: 17.5% of baggage fee

Step-by-step explanation:

4 0
3 years ago
1 is 25% of what numder
allsm [11]

Answer:

4, it's obvious think of it as a quarter.

Step-by-step explanation:

1 = 25%

2 = 50%

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5 0
3 years ago
There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3
jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0
3 years ago
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