How many brands of raisin bran are shown in the table?

nordsb [41]

Answer: multiple them all together or add them

Step-by-step explanation:

6 0

2 years ago

a group of students arrange a picnic each student contributed rupees 61 1 upon 2 the total contribution was rupees 676 1 upon 2

IrinaVladis [17]

Answer:

Now, each student contributes= Rs 61 1/2= Rs 123/2 ( mixed fraction ).

Therefore, total no. of students=Rs (1953/2÷123/2) = 15.87

Rounding off 15.87 to 16.

There were 16 students

(i hope it is correct answer. pls mark as brainliest)

8 0

3 years ago

Read 2 more answers

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

2 years ago

For the following exercises, solve each inequality and write the solution in interval notation.

Pie

Answer:

The solution of the given set in interval form is $(-\infty,-4] \cup[12, \infty)$ .

Step-by-step explanation:

It is given in the question an inequality as $|x-4| \geq 8$ .

It is required to determine the solution of the inequality.

To determine the solution of the inequality, solve the inequality $x-4 \geq 8$ and, $x-4 \leq-8$

Step 1 of 2

Solve the inequality $x-4 \geq 8$

$\begin{aligned}&x-4 \geq 8 \\&x-4+4 \geq 8+4 \\&x \geq 12\end{aligned}$

Solve the inequality $x-4 \leq-8$ .

$\begin{aligned}&x-4 \leq-8 \\&x-4+4 \leq-8+4 \\&x \leq-4\end{aligned}$

Step 2 of 2

The common solution from the above two solutions is x less than -4 and $x \geq 12$ .

The solution set in terms of interval is $(-\infty,-4] \cup[12, \infty)$ .

7 0

1 year ago

Observe os pontos Z, Y, W, X e V marcados na reta numérica abaixo.

adelina 88 [10]

Y

A raiz quadrada de 14 seria 3.74165738677 ou 3.7

Arredondamos para 4 já q 7 é próximo de 10

5 0

2 years ago