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Marat540 [252]
3 years ago
12

Fantasy Lanes bowling alley charges each patron $3 to rent shoes plus $5 per hour for bowling. This relationship is represented

by the equation
y = 5x + 3. What does the graph of this equation represent? There may be more than one correct answer.
Mathematics
1 answer:
jeka57 [31]3 years ago
7 0
It is a line
it represents te relationship between the cost and time bought
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A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
2 years ago
A large botanical garden has a total of 500 trees, bushes, and cacti. Pie chart with the following pieces: blue section titled t
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There are 190 trees.
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A contractor digs a hole for the basement of a new house that is 40 feet long and 10 1/2 feet deep. What is the width of the hol
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Volume = L * W * D 6,510
= 40 * W * 10.5
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A company is producing a new product. Due to the nature of the​ product, the time required to produce each unit decreases as wor
balu736 [363]

Answer:

The total time to produce units 1 through 10 = 21.762 hours

The total time to produce units 30 through 40 = 22.187 hours

Step-by-step explanation:

Function for the learning process is T(x) = 2 + 0.6(1/x)

Time required to produce 1st unit = 2.6

Time required to produce 2nd unit = 2.3

Time required to produce 3rd unit = 2.2

Time required to produce 4th unit = 2.15

Time required to produce 5th unit = 2.12

Time required to produce 6th unit = 2.1

Time required to produce 7th unit = 2.09

Time required to produce 8th unit = 2.075

Time required to produce 9th unit = 2. 067

Time required to produce 10th unit = 2. 06

The total time required for a new worker to produce units 1 through 10 is the sum of the above times. The total time to produce units 1 through 10 = 21.762

Function for the learning process is T(x) = 2 + 0.6(1/x)

Time required to produce 30th unit = 2.02

Time required to produce 31st unit = 2.019

Time required to produce 32nd unit = 2.0188

Time required to produce 33rd unit = 2.018

Time required to produce 34th unit = 2.0176

Time required to produce 35th unit = 2.017

Time required to produce 36th unit = 2.0167

Time required to produce 37th unit = 2.016

Time required to produce 38th unit = 2.0158

Time required to produce 39th unit = 2. 0154

Time required to produce 40th unit = 2. 015

The total time required for a new worker to produce units 30 through 40 is the sum of the above times. The total time to produce units 30 through 40 = 22.187

7 0
2 years ago
If f(x) = 5x and g(x) = -2x + 1 find f[g(-2)]
dangina [55]

Answer:

25

Step-by-step explanation:

g(-2) = -2(-2)+1 = 5

f(g(-2))=f(5) = 5(5) = 25

8 0
2 years ago
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