Answer:
The probability that the household has only cell phones and has high-speed Internet is 0.408
Step-by-step explanation:
Let A be the event that represents U.S. households has only cell phones
Let B be the event that represents U.S. households have high-speed Internet.
We are given that 51% of U.S. households has only cell phones
P(A)=0.51
We are given that 70% of the U.S. households have high-speed Internet.
P(B)=0.7
We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.
P(B|A)=0.8

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408
f(-10) = 4
f(-2) = 4
Since y is constant while x isnt we just dont need to put x
f(x) = 4
Answer: y = (xm)/3 + b
Step-by-step explanation:
1. Multiply m on both sides
x × m = 3(y - b)
2. Divide by 3 on both sides
(xm)/3 = y - b
3. Add b on both sides
y = (xm)/3 + b
Answer:
The p value for this case would be given by:
For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG
Step-by-step explanation:
Information given
represent the sample mean
represent the population standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Since we know the population deviation, the statistic is given by
(1)
Replacing we got:
The p value for this case would be given by:
For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG