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oksano4ka [1.4K]
3 years ago
5

three miners esch dup up 3 diamonds. the weight of the diamonds were 5,13,12,4,9,8,15,210, and 6 ounces of a piece. each of jack

s diamonds weighed half as mich as mark's diamonds. what was the total weight of nico's diamonds?
Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

The total weight of Nico's diamond is 564 ounces

<h3>Weights</h3>

The weights of the diamond are given as:

5, 13, 12, 4, 9, 8, 15, 210, and 6 ounces

<h3>Total weights</h3>

Start by calculating the total weights

Total = 5+13+12+4+9+8+15+210+6

Total = 282

The above sum represents the total weights of Jack's diamonds.

So, the total weights of Nico's diamond is calculated as:

Nico = 2 \times 282

Nico = 564

Hence, the total weight of Nico's diamond is 564 ounces

Read more about sum and addition at:

brainly.com/question/4344214

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PLEASE HELP
sweet [91]

Answer:

a)2 + 3 + 5 + 6 = 16

b)8a + b-9

c)8a - 28b + 15c

Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

2 + 3 + 5 + 6

Since all the terms are like terms, we can write,

2 + 3 + 5 + 6 = 16

2. Sum of given expression

(8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9

3. Standard form of the expression

4(2a) + 7(-4b) + (3 \times c \times 5)\\=(8a) + (-28b) + (15c)\\=8a - 28b + 15c

which is the required standard form of the given expression.

8 0
3 years ago
a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

                                                                            = 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

                                            = 25600 m²

Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

6 0
2 years ago
GIVING BRAINLIEST TO WHOEVER ANSWERS FIRST! ASAP<br><br>Answer 2 and 3 that's all!​
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X - 0, 1, 2, 3
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5 0
3 years ago
Please help asap....
Andrei [34K]

Find the area of the total circle and when you find that area, multiply it by 145/360 for that is how much of the circle that area is.

Area of circle, \pir^2 and 13.69 times 3.14 is 42.9866. Then multiply by 145/360 to get about 17.3 inches squared.

7 0
3 years ago
The base of a bicycle ramp has an area of 4 square feet. The ramp is a triangular prism. If the ramp has a height of 2 1/2 feet,
Anastaziya [24]

Answer:


Step-by-step explanation:

In general:

Volume = (the area of the base of the figure) times (the figure's height)

Here, the area of the base is 4 square feet, the height is 2 1/2 foot = 5/2 foot

Our Volume is then:

4 square feet * 5/2 foot = 10 cubic feet

4 0
3 years ago
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