In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
1,2 and 5 is the answers I think
The answer is D and it is the correct answer
2x - 14y = -16
Move all the terms without the variable on the other side of the equation. Add 14y to both sides of the equation.
2x = -16 + 14y
Divide both sides by 2.
x = -8 + 7y is your answer.
If we say dilation, we mean to say that the endpoints or the corners of the polygon is move by the number of scale factors away from the original point. Unfortunately, you missed to give here an illustration of both quadrilaterals, it would have been easy for us to answer this item should we have been given with the dimensions.