Answer: 1/6
Step-by-step explanation:
Probability of getting heads or tail is:
P (H) = P(T) = 1/2
The probability of getting any number on the die is:
P (1) = P (2) = P(3) = P (4) = P (5) = P (6) = 1/6
The probability of getting a tail on the coin and a number less than 3 on the die is:
![P($Tails and a number less than 3$)=P($Tails$) \times P$(A number less than 3)$$\begin{aligned}&=\frac{1}{2} \times[P(1)+P(2)] \\&=\frac{1}{2} \times\left[\frac{1}{6}+\frac{1}{6}\right] \\&=\frac{1}{6}\end{aligned}$$](https://tex.z-dn.net/?f=P%28%24Tails%20and%20a%20number%20less%20than%203%24%29%3DP%28%24Tails%24%29%20%5Ctimes%20P%24%28A%20number%20less%20than%203%29%24%24%5Cbegin%7Baligned%7D%26%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%5BP%281%29%2BP%282%29%5D%20%5C%5C%26%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%5Cleft%5B%5Cfrac%7B1%7D%7B6%7D%2B%5Cfrac%7B1%7D%7B6%7D%5Cright%5D%20%5C%5C%26%3D%5Cfrac%7B1%7D%7B6%7D%5Cend%7Baligned%7D%24%24)
Therefore the required of getting tails and a number less than 3 is 1/6
7. v = 15
8. n = -6
9. x = 9
10. n = 8
11. v = -16
12. x = -17
I apologise but, what expression?
Answer:
Step-by-step explanation:
Each child received two pieces.
So total pieces received by 4 children = 4*2 = 8
Total pieces = 10 + 8 = 18
Answer:
C and F
Step-by-step explanation: