I dont understand this what do the numbers represent
Given A = {(1, 3)(-1, 5)(6, 4)}, B = {(2, 0)(4, 6)(-4, 5)(0, 0)} and C = {(1, 1)(0, 2)(0, 3)(0, 4)(-3, 5)}, answer the following
Nuetrik [128]
Answer:
Domain of set B: {2, 4, -4, 0}
Step-by-step explanation:
The domain of the function whose ordered pairs are listed in set B is the set of first numbers of those pairs: {2, 4, -4, 0}.
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<em>Comment on the question</em>
A "set" does not have a domain. A "function" has a domain. To make any sense of this question, we have to interpret the question to mean the function described by the ordered pairs in the set.
121 over 121 is a whole number of 1
Answer:
Exponent laws:
1. Product law

In product law if bases are same then we add their respective powers.But if bases are different we can't add their powers.
x=base, a,b,c=exponent
If x=2 and a=3, b=5 , and c=10, then

2.Product raised to a power
1. ![[x^{a}]^{c}=x^{ac}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%7D)
2. ![[x^{a}\times x^{b}]^{c}=[x^{a+b}]^{c}=x^{ac+bc}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5Ctimes%20x%5E%7Bb%7D%5D%5E%7Bc%7D%3D%5Bx%5E%7Ba%2Bb%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%2Bbc%7D)
If product is raised to a certain power , keeping the base same , we just multiply the powers.for example
and
![[2^{3}\times3^{2}]^{2}=[2^{3}]^2 \times[3^{2}]^{2}=2^{6}\times3^{4}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes3%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%7D%5D%5E2%20%5Ctimes%5B3%5E%7B2%7D%5D%5E%7B2%7D%3D2%5E%7B6%7D%5Ctimes3%5E%7B4%7D)
![[2^{3}\times2^{2}]^{2}=[2^{3+2}]^{2}=[2^{5}]^{2}=2^{10}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes2%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%2B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B5%7D%5D%5E%7B2%7D%3D2%5E%7B10%7D)