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Free_Kalibri [48]
2 years ago
6

One of the legs of a right triangle measures 2 cm and its hypotenuse measures 18 cm.

Mathematics
1 answer:
denpristay [2]2 years ago
4 0

Answer:

17.9

Step-by-step explanation:

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the baker's at healthy Bakery can make 250 Bagels in the five hours how many bagels can they bake in 16 hours what was the rate
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Kala has been offered two 40 hour a week jobs. One job pays an hourly wage of $25 and 10% of all sales. The other job pays $20 a
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(40 * 25) + 0.10x = (40 * 20) + 0.20x
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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0
3 years ago
13501 rounded to nearest 10000
Shtirlitz [24]
14,000 is the correct answer
5 0
3 years ago
Read 2 more answers
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