=-2i
you flip it to the reciprocal which would be -2i
You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
x = −
4 ± √
10,
Step-by-step explanation:
2(x + 4)² = 20
=> 2(x + 4) (x + 4) = 20
=> 2x + 8 (x + 4) = 20
=> 2x² + 8x + 8x + 32 = 20
=> 2x² + 16x + 32 = 20
=> 2x² + 16x + 12 = 0
=> Now solve using the quadratic formula:
x = −
4 ± √
10,
Radical form: −
4 ± √
10,
Decimal form: -0.84, -7.16
Hope this helps!
The answer to this question is D
Answer:
![25x+12y+4 \leq 130](https://tex.z-dn.net/?f=25x%2B12y%2B4%20%5Cleq%20130)
Step-by-step explanation:
Here, x represents the number of tickets and y represents the number of T-shirts.
As per the statement:
Each ticket costs $25, and souvenir T-shirts are $12 each
⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y
It is also given that there is a $4 service fee for the entire purchase.
![25x+12y+4](https://tex.z-dn.net/?f=25x%2B12y%2B4)
Since, she has $130
⇒![25x+12y+4 \leq 130](https://tex.z-dn.net/?f=25x%2B12y%2B4%20%5Cleq%20130)
Therefore, an inequality could you use to answer the problem is, ![25x+12y+4 \leq 130](https://tex.z-dn.net/?f=25x%2B12y%2B4%20%5Cleq%20130)