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egoroff_w [7]
3 years ago
13

Please explain and answer Part C. I will give 20 points

Mathematics
1 answer:
madam [21]3 years ago
6 0

assuming the rest of your math is correct, the cone would have an area of roughly 212 sq in and the bowl roughly 157 sq inches. Therefore the one with less area is cheaper to make

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Answer:

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Step-by-step explanation:

Given:

Area of link shaded regions = 84 cm²

Required:

The value of x (diameter of the semicircle/length of the rectangle)

Solution:

Diameter of the semicircle = 2r = x

Length of rectangle (L) = 2r = x

Radius of semicircle (r) = ½x

Width of rectangle (W) = radius of semicircle = ½x

Use 3.14 as π

Area of the link shaded regions = area of rectangle - area of semicircle

Thus:

Area of the link shaded regions = (L*W) - (½*πr²)

Plug in the values

84 = (x*½x) - (½*3.14*(½x)²)

84 = x²/2 - (1.57*x²/4)

84 = x²(½ - 1.57/4)

84 = x²(0.5 - 0.3925)

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√781.4 = x

27.9535329 = x

x = 28 cm

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