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mina [271]
3 years ago
7

The force of an object (f) is equal to its mass (m) times its acceleration (a). Thus, the formula for calculating force is f = m

a. Based on this information, which of the following equations would be used to calculate acceleration? A. a = fm B. a = f ÷ m C. a = f + m D. a = f − m
Mathematics
2 answers:
natima [27]3 years ago
6 0
Hello There! Sorry for the late answer, but better late than never as they say! The correct answer to your query is B: A= F divided by m. Please tell me if this helps any or not.
julia-pushkina [17]3 years ago
5 0

B) A=F/B i just took the test

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11. In a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16. What is the mean for
ahrayia [7]

Answer:

11

Step-by-step explanation:

Given that in a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16

i.e. the data entries are

10,10,10,10,10,16

Sum = 66

No of items n = 6

Average = sum/no of entries

=\frac{66}{6} \\=11

Average is 11.

mean of this sample is 11

8 0
3 years ago
Plz help me I’m not good at math
grigory [225]

Answer:

second one

Step-by-step explanation:

am pretty sure

6 0
3 years ago
Read 2 more answers
Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Show the correct substitution of the values
Grace [21]
I hope this helps you

5 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
I NEED HELP ASAP PLS<br><br> Select the correct graphed line for the equation below.
ddd [48]
2. Sorry if I’m wrong but that’s what I just put
4 0
3 years ago
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