(work)(study) + (work)(practice) + (work)(perseverance)

Mathematics

1 answer:

kolezko [41]2 years ago

5 0

9514 1404 393

Answer:

(work)(study + practice + perseverance)

Step-by-step explanation:

(work) is the common factor in the three products. It can be factored out:

(work)(study + practice + perseverance)

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Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

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3 years ago

Line segment AB has endpoints A(1, 4) and B(2, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has en

kumpel [21]

To determine the scale factor of the dilation, we determine the distances between the endpoints of the two lines through the equation,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Substituting the known values.

Line Segment 1: d = √(1 - 2)² + (4 - 8)² = 4.123

Line Segment 2: d = √(18 - 14)² + (12 - 1)² = 11.70

Dividing the answers will give us 0.352

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3 years ago

Read 2 more answers

Round 0.977 to the nearest hundredth

UkoKoshka [18]

.98 since the hundredth place is higher than a five it is rounded up

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3 years ago

23 increased by twice Vanessa’s scare

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I’m stuck on it too!

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