Explain how pumping air into a bicycle tire increases the presssure
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Hello!
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
</span>
I hope this helps. =)
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
</span>
I hope this helps. =)