Answer: D
Explanation:
London forces become stronger as the atom in question becomes larger, and to a smaller degree for large molecules. [4] This is due to the increased polarizability of molecules with larger, more dispersed electron clouds. The polarizability is a measure of ease with which electrons can be redistributed; a large polarizability implies that the electrons are more easily redistributed. This trend is exemplified by the halogens (from smallest to largest: F 2 , Cl2 , Br 2 , I 2 ). The same increase of dispersive attraction occurs within and between organic molecules in the order RF<RCL<RBr<RI, or with other more polarizable heteroatoms. [5] Fluorine and chlorine are
gases at room temperature, bromine is a liquid, and iodine is a solid. The London forces are thought to be arise from the motion of electrons.
Answer:
If a metal and metal solution react, the more reactive metal will displace the less reactive metal from solution. If the metal in solution you start with is formed from a more reactive metal than the metal to be added, no reaction will occur.
The reaction formula is 2HCl + Mg = MgCl2 + H2. There are one atom of magnesium involved and the number of atoms will not change, So the answer is one magnesium ion.
<h3>
Answer:</h3>
0.3093 g of glucose are consumed each minute by the body.
<h3>
Explanation:</h3>
- During cellular respiration glucose is broken down in presence of oxygen to yield energy, water and carbon dioxide.
- The equation for the reaction taking place during cellular respiration is;
C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂
We are required to calculate the amount of glucose in grams;
<h3>Step 1: Calculate the moles of glucose broken down</h3>
From the equation, the mole ratio of glucose to Oxygen is 1 : 6
Moles of Oxygen in a minute is 1.03 × 10^-2 moles
Therefore, moles of glucose will be;
= (1.03 × 10^-2)÷6
= 1.717 × 10^-3 moles
<h3>Step 2: Mass of glucose </h3>
Mass is given by multiplying the number of moles with molar mass
mass = moles × molar mass
Molar mass glucose is 180.156 g/mol
Therefore;
Mass = 1.717 × 10^-3 × 180.156 g/mol
= 0.3093 g
Hence, 0.3093 g of glucose are consumed each minute by the body.
